What is y^2-10y-12x+37=0 ?

The solution to y^2-10y-12x+37=0 is Parabola with (h,k)=(1,5),p=3

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y^2-10y-12x+37=0

y^{2} - 10 y - 12 x + 37 = 0

(h, k) = (1, 5), p = 3

Solution steps

y^{2} - 10 y - 12 x + 37 = 0

Rewrite

y^{2} - 10 y - 12 x + 37 = 0

in the standard form

4 \cdot 3 (x - 1) = (y - 5)^{2}

Therefore parabola properties are:

(h, k) = (1, 5), p = 3

\frac{x ^{2}}{a ^{2}} - \frac{y ^{2}}{b ^{2}} = 1

f (x) = x^{2} - 2 x

\frac{x ^{2}}{25} + \frac{y ^{2}}{9} = 1

x^{2} - \frac{y ^{2}}{16} = 1

f (x) = (x - 5) (x + 1)

What is y^2-10y-12x+37=0 ?
The solution to y^2-10y-12x+37=0 is Parabola with (h,k)=(1,5),p=3