What is x^2-(y^2)/(16)=1 ?

The solution to x^2-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=1,b=4

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x^2-(y^2)/(16)=1

x^{2} - \frac{y ^{2}}{16} = 1

(h, k) = (0, 0), a = 1, b = 4

Solution steps

x^{2} - \frac{y ^{2}}{16} = 1

Rewrite

x^{2} - \frac{y ^{2}}{16} = 1

in the form of a standard hyperbola equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} - \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (0, 0), a = 1, b = 4

f (x) = (x - 5) (x + 1)

x^{2} + (y - 4)^{2} = 4

x^{2} - 6 x + 5 y = - 34

f (x) = x^{2} - 2 x - 3

y + x^{2} = 4 x

What is x^2-(y^2)/(16)=1 ?
The solution to x^2-(y^2)/(16)=1 is Hyperbola with (h,k)=(0,0),a=1,b=4