What is x^2+y^2-6x+4y+4=0 ?

The solution to x^2+y^2-6x+4y+4=0 is Circle with (a,b)=(3,-2),r=3

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x^2+y^2-6x+4y+4=0

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

(a, b) = (3, - 2), r = 3

Solution steps

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

Rewrite

x^{2} + y^{2} - 6 x + 4 y + 4 = 0

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 2))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (3, - 2), r = 3

y = \frac{1}{2} x^{2}

\frac{y ^{2}}{9} - \frac{x ^{2}}{4} = 1

x^{2} = 3 y

\frac{a + 1}{b} = \frac{a - 1}{b} + \frac{b + 1}{a}

\frac{x ^{2}}{4} + \frac{y ^{2}}{9} = 1

What is x^2+y^2-6x+4y+4=0 ?
The solution to x^2+y^2-6x+4y+4=0 is Circle with (a,b)=(3,-2),r=3