What is x^2+y^2+10x-4y-7=0 ?

The solution to x^2+y^2+10x-4y-7=0 is Circle with (a,b)=(-5,2),r=6

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x^2+y^2+10x-4y-7=0

x^{2} + y^{2} + 10 x - 4 y - 7 = 0

(a, b) = (- 5, 2), r = 6

Solution steps

x^{2} + y^{2} + 10 x - 4 y - 7 = 0

Rewrite

x^{2} + y^{2} + 10 x - 4 y - 7 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 2)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (- 5, 2), r = 6

y^{2} = - 10 x

x^{2} = 8 y

(x + 6)^{2} + \frac{( y + 4 ) ^{2}}{\frac{1}{4}} = 1

\frac{x ^{2}}{25} + \frac{y ^{2}}{16} = 1

\frac{y ^{2}}{36} - \frac{x ^{2}}{64} = 1

What is x^2+y^2+10x-4y-7=0 ?
The solution to x^2+y^2+10x-4y-7=0 is Circle with (a,b)=(-5,2),r=6