What is 2(3)^2+3(3)+1 ?

The solution to 2(3)^2+3(3)+1 is 28

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2(3)^2+3(3)+1

2 (3)^{2} + 3 (3) + 1

28

Solution steps

2 (3)^{2} + 3 (3) + 1

Follow the PEMDAS order of operations

Calculate exponents

(3)^{2} : 9

(3)^{2}

(3)^{2} = 9

= 9

= 2 \cdot 9 + 3 (3) + 1

Multiply and divide (left to right)

2 \cdot 9 : 18

2 \cdot 9

2 \cdot 9 = 18

= 18

= 18 + 3 (3) + 1

Multiply and divide (left to right)

3 (3) : 9

3 (3)

Apply rule:

(a) = a

(3) = 3

= 3 \cdot 3

Multiply the numbers:

3 \cdot 3 = 9

= 9

= 18 + 9 + 1

Add and subtract (left to right)

18 + 9 + 1 : 28

18 + 9 + 1

18 + 9 = 27

= 27 + 1

27 + 1 = 28

= 28

= 28

- 4 (6 - 9 + 1) - 4 - 9

2^{5} - 1 - 5

2 + (- 9) + (- 2) + 8

- (1)^{2} + 3 (1) + 2

6 \div 2 (+ 2)