What is 16\div 2-4^2-(-3)^2 ?

The solution to 16\div 2-4^2-(-3)^2 is -17

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16\div 2-4^2-(-3)^2

16 \div 2 - 4^{2} - (- 3)^{2}

- 17

Solution steps

16 \div 2 - 4^{2} - (- 3)^{2}

Follow the PEMDAS order of operations

Calculate exponents

4^{2} : 16

4^{2}

4^{2} = 16

= 16

= 16 \div 2 - 16 - (- 3)^{2}

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 16 \div 2 - 16 - 9

Multiply and divide (left to right)

16 \div 2 : 8

16 \div 2

16 \div 2 = 8

= 8

= 8 - 16 - 9

Add and subtract (left to right)

8 - 16 - 9 : - 17

8 - 16 - 9

8 - 16 = - 8

= - 8 - 9

- 8 - 9 = - 17

= - 17

= - 17

\frac{- 16 - ( - 8 ) ( - 20 )}{( - 11 ) ( - 8 )}

4 + 2 [5 + 3 (6 + 2)]

\frac{1}{5} + \frac{3}{8}

- 3 - 5 + 7 + 7

2 0^{2} - 2 9^{2}