What is 3(1)^2-6(1)+4 ?

The solution to 3(1)^2-6(1)+4 is 1

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3(1)^2-6(1)+4

3 (1)^{2} - 6 (1) + 4

1

Solution steps

3 (1)^{2} - 6 (1) + 4

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 3 \cdot 1 - 6 (1) + 4

Multiply and divide (left to right)

3 \cdot 1 : 3

3 \cdot 1

3 \cdot 1 = 3

= 3

= 3 - 6 (1) + 4

Multiply and divide (left to right)

6 (1) : 6

6 (1)

Apply rule:

(a) = a

(1) = 1

= 6 \cdot 1

Multiply the numbers:

6 \cdot 1 = 6

= 6

= 3 - 6 + 4

Add and subtract (left to right)

3 - 6 + 4 : 1

3 - 6 + 4

3 - 6 = - 3

= - 3 + 4

- 3 + 4 = 1

= 1

= 1

35 - 1 - 2 - 2 - 2 - 2 - 2 - 2 - 5

2 - ((2 + 1) - (3 + 2))

2 \cdot 5^{4}

2 \times (- 3)^{2} - (- 3) + 2

11 - 4 + 13 - 2 - 6 + 3