What is 3(4)^2-6(4)+1 ?

The solution to 3(4)^2-6(4)+1 is 25

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3(4)^2-6(4)+1

3 (4)^{2} - 6 (4) + 1

25

Solution steps

3 (4)^{2} - 6 (4) + 1

Follow the PEMDAS order of operations

Calculate exponents

(4)^{2} : 16

(4)^{2}

(4)^{2} = 16

= 16

= 3 \cdot 16 - 6 (4) + 1

Multiply and divide (left to right)

3 \cdot 16 : 48

3 \cdot 16

3 \cdot 16 = 48

= 48

= 48 - 6 (4) + 1

Multiply and divide (left to right)

6 (4) : 24

6 (4)

Apply rule:

(a) = a

(4) = 4

= 6 \cdot 4

Multiply the numbers:

6 \cdot 4 = 24

= 24

= 48 - 24 + 1

Add and subtract (left to right)

48 - 24 + 1 : 25

48 - 24 + 1

48 - 24 = 24

= 24 + 1

24 + 1 = 25

= 25

= 25

(- 2)^{3} \times 4^{2} - 10

- 3 + (3 \times 7 + 12) + 4 - 12

3^{2} \div (- 3)^{2}

- 3 \times (- 2) (3 \times (- 4))

12 \times 10 + 30 \div (6 - 3) \times 4 + 1