What is 2(1)^2-4(1)+2 ?

The solution to 2(1)^2-4(1)+2 is 0

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2(1)^2-4(1)+2

2 (1)^{2} - 4 (1) + 2

0

Solution steps

2 (1)^{2} - 4 (1) + 2

Follow the PEMDAS order of operations

Calculate exponents

(1)^{2} : 1

(1)^{2}

(1)^{2} = 1

= 1

= 2 \cdot 1 - 4 (1) + 2

Multiply and divide (left to right)

2 \cdot 1 : 2

2 \cdot 1

2 \cdot 1 = 2

= 2

= 2 - 4 (1) + 2

Multiply and divide (left to right)

4 (1) : 4

4 (1)

Apply rule:

(a) = a

(1) = 1

= 4 \cdot 1

Multiply the numbers:

4 \cdot 1 = 4

= 4

= 2 - 4 + 2

Add and subtract (left to right)

2 - 4 + 2 : 0

2 - 4 + 2

2 - 4 = - 2

= - 2 + 2

- 2 + 2 = 0

= 0

= 0

3 \times (- 5) + 23 \times (- 9)

3 (- 2)^{4} + 3 (- 2)^{3} - 2 (- 2) + 1

- 2 - 2 + 6

12 \times 56 - 6 \times 12

1^{2} + 2 (1) + 1