What is 6+4[3(62)/12] ?

The solution to 6+4[3(62)/12] is 68

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6+4[3(62)/12]

6 + 4 [3 (62) /12]

68

Solution steps

6 + 4 [3 (62) /12]

Follow the PEMDAS order of operations

Calculate within parentheses

[3 (62) /12] : \frac{186}{12}

3 (62) /12

Multiply and divide (left to right)

3 (62) = 186

3 (62)

Apply rule:

(a) = a

(62) = 62

= 3 \cdot 62

Multiply the numbers:

3 \cdot 62 = 186

= 186

= 186/12

186/12 = \frac{186}{12}

= \frac{186}{12}

= 6 + 4 \cdot \frac{186}{12}

Multiply and divide (left to right)

4 \cdot \frac{186}{12} : 62

4 \cdot \frac{186}{12}

Cancel

\frac{186}{12} : \frac{31}{2}

\frac{186}{12}

Factor the number:

186 = 6 \cdot 31

= \frac{6 \cdot 31}{12}

Factor the number:

12 = 6 \cdot 2

= \frac{6 \cdot 31}{6 \cdot 2}

Cancel the common factor:

6

= \frac{31}{2}

= 4 \cdot \frac{31}{2}

4 \cdot \frac{31}{2} = 62

4 \cdot \frac{31}{2}

Convert element to fraction:

4 = \frac{4}{1}

= \frac{4}{1} \cdot \frac{31}{2}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 \cdot 31}{1 \cdot 2}

Cancel

\frac{4 \cdot 31}{1 \cdot 2} : 62

\frac{4 \cdot 31}{1 \cdot 2}

Multiply the numbers:

1 \cdot 2 = 2

= \frac{4 \cdot 31}{2}

Divide the numbers:

\frac{4}{2} = 2

= 2 \cdot 31

Multiply the numbers:

2 \cdot 31 = 62

= 62

= 62

= 62

= 6 + 62

Add and subtract (left to right)

6 + 62 : 68

6 + 62

6 + 62 = 68

= 68

= 68

8 + 4 \times 4^{2} + 10 \times 6

\frac{- 1 - 4}{- 1 - 3}

\frac{5 0 ^{2} - 8 0 ^{2}}{2}

16 (12)^{2}

9 - 2 [- 4 (4 - 8) - 3 (6 - 4)]