What is 3(-3)^2-5(-3)-2 ?

The solution to 3(-3)^2-5(-3)-2 is 40

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3(-3)^2-5(-3)-2

3 (- 3)^{2} - 5 (- 3) - 2

40

Solution steps

3 (- 3)^{2} - 5 (- 3) - 2

Follow the PEMDAS order of operations

Calculate exponents

(- 3)^{2} : 9

(- 3)^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- 3)^{2} = 3^{2} = 9

= 9

= 3 \cdot 9 - 5 (- 3) - 2

Multiply and divide (left to right)

3 \cdot 9 : 27

3 \cdot 9

3 \cdot 9 = 27

= 27

= 27 - 5 (- 3) - 2

Multiply and divide (left to right)

5 (- 3) : - 15

5 (- 3)

Apply rule

a \cdot (- b) = - a \cdot b

5 (- 3) = - 5 \cdot 3 = - 15

= - 15

= 27 - (- 15) - 2

Add and subtract (left to right)

27 - (- 15) - 2 : 40

27 - (- 15) - 2

Apply rule

- (- a) = + a

- (- 15) = + 15

= 27 + 15 - 2

27 + 15 = 42

= 42 - 2

42 - 2 = 40

= 40

= 40

7 - [2 \times 9 - (4 + 13) + 4 \div 2]

15 \div (- 5) - (- 18) \div (- 2) + (- 32) \div (- 8)

0 + (- 3 - 2)^{2}

- 2 (- 3) - 3

(- 1)^{0} - 2^{1} + (- 3)^{2} + (- 2)^{3}