What is the derivative of y=ln(ln(x^{32})) ?

The derivative of y=ln(ln(x^{32})) is (32)/(xln(x^{32))}

What is the first derivative of y=ln(ln(x^{32})) ?

The first derivative of y=ln(ln(x^{32})) is (32)/(xln(x^{32))}

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derivative of

y = ln (ln (x^{32}))

\frac{32}{x ln ( x ^{32} )}

Solution steps

\frac{d}{d x} (ln (ln (x^{32})))

Apply the chain rule:

\frac{1}{ln ( x ^{32} )} \frac{d}{d x} (ln (x^{32}))

= \frac{1}{ln ( x ^{32} )} \frac{d}{d x} (ln (x^{32}))

\frac{d}{d x} (ln (x^{32})) = \frac{32}{x}

= \frac{1}{ln ( x ^{32} )} \cdot \frac{32}{x}

Simplify

\frac{1}{ln ( x ^{32} )} \cdot \frac{32}{x} : \frac{32}{x ln ( x ^{32} )}

= \frac{32}{x ln ( x ^{32} )}

4 x - 3 y = 9

y = x^{2} - 3 x - 10, at x = 5.5

(- 1) (0) (4)

y = e^{x^{2}}

f (x) = - \frac{9}{x}, at x = 6

What is the derivative of y=ln(ln(x^{32})) ?
The derivative of y=ln(ln(x^{32})) is (32)/(xln(x^{32))}
What is the first derivative of y=ln(ln(x^{32})) ?
The first derivative of y=ln(ln(x^{32})) is (32)/(xln(x^{32))}