What is the perpendicular y=3x-2,(3,7) ?

The perpendicular y=3x-2,(3,7) is y=-1/3 x+8

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perpendicular y=3x-2,(3,7)

perpendicular

y = 3 x - 2, (3, 7)

y = - \frac{1}{3} x + 8

Solution steps

Find the line

y = mx + b

perpendicular to

y = 3 x - 2

that passes through

(3, 7)

Find the slope of

y = 3 x - 2 : m = 3

Compute the slope of the perpendicular line:

m_{p} = - \frac{1}{3}

Find the line with slope m=

- \frac{1}{3}

and passing through

(3, 7) : y = - \frac{1}{3} x + 8

y = - \frac{1}{3} x + 8

f (x) = sec^{2} (x)

y = 3 x^{3} + \frac{1}{4} x^{2}

f (x) = e^{x} + 2 e^{2 x}

(0, - 5)

f (x) = x^{2}, at x = 3

What is the perpendicular y=3x-2,(3,7) ?
The perpendicular y=3x-2,(3,7) is y=-1/3 x+8