What is the tangent of f(x)=sin(2x)cos(x),\at x=pi ?

The tangent of f(x)=sin(2x)cos(x),\at x=pi is y=-2x+2pi

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tangent of f(x)=sin(2x)cos(x),\at x=pi

tangent of

f (x) = sin (2 x) cos (x), at x = π

y = - 2 x + 2 π

Solution steps

Find the tangent point:

(π, 0)

Find the slope of

f (x) = sin (2 x) cos (x) : \frac{df ( x )}{d x} = 2 cos (2 x) cos (x) - sin (x) sin (2 x)

Compute the slope of

f (x) = sin (2 x) cos (x)

x = π : m = - 2

Find the line with slope m=

- 2

and passing through

(π, 0) : y = - 2 x + 2 π

y = - 2 x + 2 π

f (x) = (x^{2} + 1)^{2}

x = - 1

x = 4

f (x) = \frac{3}{x ^{2}}

y = 3 x^{2}

What is the tangent of f(x)=sin(2x)cos(x),\at x=pi ?
The tangent of f(x)=sin(2x)cos(x),\at x=pi is y=-2x+2pi