What is the derivative of f(x)= 1/(x^2) ?

The derivative of f(x)= 1/(x^2) is -2/(x^3)

What is the first derivative of f(x)= 1/(x^2) ?

The first derivative of f(x)= 1/(x^2) is -2/(x^3)

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derivative of

f (x) = \frac{1}{x ^{2}}

- \frac{2}{x ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{x ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} (x^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 x^{- 2 - 1}

Simplify

- 2 x^{- 2 - 1} : - \frac{2}{x ^{3}}

= - \frac{2}{x ^{3}}

f (x) = sin (x^{2})

3 x + 5 y - 3 = 0

y = x sin (x)

ln (x)

f (x) = x

What is the derivative of f(x)= 1/(x^2) ?
The derivative of f(x)= 1/(x^2) is -2/(x^3)
What is the first derivative of f(x)= 1/(x^2) ?
The first derivative of f(x)= 1/(x^2) is -2/(x^3)