en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

midpoint (3,-5),(7,9)

Solution

midpoint

(3, - 5), (7, 9)

Solution

(5, 2)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

:

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, - 5), (x_{2}, y_{2}) = (7, 9)

= (\frac{7 + 3}{2}, \frac{9 - 5}{2})

Refine

= (5, 2)

Popular Examples

derivative of 2x*e^{x^2}derivative of

2 x \cdot e^{x^{2}}

extreme f(x,y)=-e^{x-y^2+xy}extreme points

f (x, y) = - e^{x - y^{2} + x y}

midpoint (15,3),(2,-14)midpoint

(15, 3), (2, - 14)

derivative of f(x)=x^2-5 derivative of

f (x) = x^{2} - 5

derivative of f(x)= x/(x-2)derivative of

f (x) = \frac{x}{x - 2}

Frequently Asked Questions (FAQ)

What is the midpoint (3,-5),(7,9) ?
The midpoint (3,-5),(7,9) is (5,2)