What is the general solution for -2cos(θ)+2sqrt(3)=sqrt(3) ?

The general solution for -2cos(θ)+2sqrt(3)=sqrt(3) is θ= pi/6+2pin,θ=(11pi)/6+2pin

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-2cos(θ)+2sqrt(3)=sqrt(3)

- 2 cos (θ) + 23 = 3

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

Degrees

θ = 3 0^{\circ} + 36 0^{\circ} n, θ = 33 0^{\circ} + 36 0^{\circ} n

Solution steps

- 2 cos (θ) + 23 = 3

Move

23

to the right side

- 2 cos (θ) + 23 = 3

Subtract

23

from both sides

- 2 cos (θ) + 23 - 23 = 3 - 23

Simplify

- 2 cos (θ) + 23 - 23 = 3 - 23

Simplify

- 2 cos (θ) + 23 - 23 : - 2 cos (θ)

- 2 cos (θ) + 23 - 23

Add similar elements:

23 - 23 = 0

= - 2 cos (θ)

Simplify

3 - 23 : - 3

3 - 23

Add similar elements:

3 - 23 = - 3

= - 3

- 2 cos (θ) = - 3

- 2 cos (θ) = - 3

- 2 cos (θ) = - 3

Divide both sides by

- 2

- 2 cos (θ) = - 3

Divide both sides by

- 2

\frac{- 2 cos ( θ )}{- 2} = \frac{- 3}{- 2}

Simplify

cos (θ) = \frac{3}{2}

cos (θ) = \frac{3}{2}

General solutions for

cos (θ) = \frac{3}{2}

cos (x)

periodicity table with

2 πn

cycle:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} cos (x) 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} cos (x) - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2} 0 \frac{1}{2} \frac{2}{2} \frac{3}{2}

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

θ = \frac{π}{6} + 2 πn, θ = \frac{11 π}{6} + 2 πn

x, 4 cos^{3} (x) = 3 cos (x)

cos^{2} (x) = 2 cos (x) - 1

11 sin (x + 37.0 9^{\circ}) = 1

cot^{2} (x) + 3 csc (x) + 3 = 0

cos (2 x) + cos (x) - 1 = 0

What is the general solution for -2cos(θ)+2sqrt(3)=sqrt(3) ?
The general solution for -2cos(θ)+2sqrt(3)=sqrt(3) is θ= pi/6+2pin,θ=(11pi)/6+2pin