What is the general solution for cos(H)=0.3648447229 ?

The general solution for cos(H)=0.3648447229 is H=1.19733…+2pin,H=2pi-1.19733…+2pin

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cos(H)=0.3648447229

cos (H) = 0.3648447229

H = 1.19733 \dots + 2 πn, H = 2 π - 1.19733 \dots + 2 πn

Degrees

H = 68.60197 \dots^{\circ} + 36 0^{\circ} n, H = 291.39802 \dots^{\circ} + 36 0^{\circ} n

Solution steps

cos (H) = 0.3648447229

Apply trig inverse properties

cos (H) = 0.3648447229

General solutions for

cos (H) = 0.3648447229

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = 2 π - arccos (a) + 2 πn

H = arccos (0.3648447229) + 2 πn, H = 2 π - arccos (0.3648447229) + 2 πn

H = arccos (0.3648447229) + 2 πn, H = 2 π - arccos (0.3648447229) + 2 πn

Show solutions in decimal form

H = 1.19733 \dots + 2 πn, H = 2 π - 1.19733 \dots + 2 πn

θ, cos (\frac{θ}{2} + 3 0^{\circ}) = sin (θ)

5 sin^{2} (θ) = 1 + 3 sin^{2} (θ)

5 sin (2 θ) - 8 sin (θ) = 0

tan (θ) = \frac{5 3}{5}

f, r = \frac{8}{sec ( f ^{0} )}

What is the general solution for cos(H)=0.3648447229 ?
The general solution for cos(H)=0.3648447229 is H=1.19733…+2pin,H=2pi-1.19733…+2pin