What is the general solution for 2sin(x)+1=0 ?

The general solution for 2sin(x)+1=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin

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2sin(x)+1=0

2 sin (x) + 1 = 0

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

Solution steps

2 sin (x) + 1 = 0

Move

1

to the right side

2 sin (x) = - 1

Divide both sides by

2

sin (x) = - \frac{1}{2}

General solutions for

sin (x) = - \frac{1}{2}

x = \frac{7 π}{6} + 2 πn, x = \frac{11 π}{6} + 2 πn

sin (- 3 0^{\circ})

cos^{2} (x) = 1

x, cos (2 x) = - \frac{3}{2}

tan (16 5^{\circ})

tan (\frac{1}{2})

What is the general solution for 2sin(x)+1=0 ?
The general solution for 2sin(x)+1=0 is x=(7pi)/6+2pin,x=(11pi)/6+2pin