What is the general solution for solvefor x,cos(2x)=-(sqrt(3))/2 ?

The general solution for solvefor x,cos(2x)=-(sqrt(3))/2 is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin

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solvefor x,cos(2x)=-(sqrt(3))/2

solve for

x, cos (2 x) = - \frac{3}{2}

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

Solution steps

cos (2 x) = - \frac{3}{2}

General solutions for

cos (2 x) = - \frac{3}{2}

2 x = \frac{5 π}{6} + 2 πn, 2 x = \frac{7 π}{6} + 2 πn

Solve

2 x = \frac{5 π}{6} + 2 πn : x = \frac{5 π}{12} + πn

Solve

2 x = \frac{7 π}{6} + 2 πn : x = \frac{7 π}{12} + πn

x = \frac{5 π}{12} + πn, x = \frac{7 π}{12} + πn

tan (16 5^{\circ})

tan (\frac{1}{2})

cos (x) - sin (x) = 0, 0 \leq x \leq 2 π

cos (x) + 1 = sin (x)

tan (21 0^{\circ})

What is the general solution for solvefor x,cos(2x)=-(sqrt(3))/2 ?
The general solution for solvefor x,cos(2x)=-(sqrt(3))/2 is x=(5pi)/(12)+pin,x=(7pi)/(12)+pin