What is the general solution for cos(x)-sin(x)=0,0<= x<= 2pi ?

The general solution for cos(x)-sin(x)=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4

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cos(x)-sin(x)=0,0<= x<= 2pi

cos (x) - sin (x) = 0, 0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

Solution steps

cos (x) - sin (x) = 0, 0 \leq x \leq 2 π

Rewrite using trig identities

1 - tan (x) = 0

Move

1

to the right side

- tan (x) = - 1

Divide both sides by

- 1

tan (x) = 1

General solutions for

tan (x) = 1

x = \frac{π}{4} + πn

Solutions for the range

0 \leq x \leq 2 π

x = \frac{π}{4}, x = \frac{5 π}{4}

cos (x) + 1 = sin (x)

tan (21 0^{\circ})

2 tan (θ) - sec^{2} (θ) = 0

arcsinh (1)

tan (\frac{π}{4})

What is the general solution for cos(x)-sin(x)=0,0<= x<= 2pi ?
The general solution for cos(x)-sin(x)=0,0<= x<= 2pi is x= pi/4 ,x=(5pi)/4