What is the general solution for 2tan(θ)-sec^2(θ)=0 ?

The general solution for 2tan(θ)-sec^2(θ)=0 is θ= pi/4+pin

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2tan(θ)-sec^2(θ)=0

2 tan (θ) - sec^{2} (θ) = 0

θ = \frac{π}{4} + πn

Solution steps

2 tan (θ) - sec^{2} (θ) = 0

Rewrite using trig identities

- 1 - tan^{2} (θ) + 2 tan (θ) = 0

Solve by substitution

tan (θ) = 1

tan (θ) = 1 : θ = \frac{π}{4} + πn

Combine all the solutions

θ = \frac{π}{4} + πn

arcsinh (1)

tan (\frac{π}{4})

sin^{2} (x) = \frac{1}{4}, 0 \leq x \leq 2 π

tan (\frac{7 π}{6})

tan^{2} (x) - 1 = 0

What is the general solution for 2tan(θ)-sec^2(θ)=0 ?
The general solution for 2tan(θ)-sec^2(θ)=0 is θ= pi/4+pin