What is the general solution for sin^2(x)= 1/4 ,0<= x<= 2pi ?

The general solution for sin^2(x)= 1/4 ,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(7pi)/6 ,x=(11pi)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sin^2(x)= 1/4 ,0<= x<= 2pi

sin^{2} (x) = \frac{1}{4}, 0 \leq x \leq 2 π

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

Solution steps

sin^{2} (x) = \frac{1}{4}, 0 \leq x \leq 2 π

Solve by substitution

sin (x) = \frac{1}{2}, sin (x) = - \frac{1}{2}

sin (x) = \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{π}{6}, x = \frac{5 π}{6}

sin (x) = - \frac{1}{2}, 0 \leq x \leq 2 π : x = \frac{7 π}{6}, x = \frac{11 π}{6}

Combine all the solutions

x = \frac{π}{6}, x = \frac{5 π}{6}, x = \frac{7 π}{6}, x = \frac{11 π}{6}

tan (\frac{7 π}{6})

tan^{2} (x) - 1 = 0

cos (2 θ) = - \frac{3}{2}

cot^{2} (13 5^{\circ}) - sin (21 0^{\circ}) + 5 cos^{2} (22 5^{\circ})

sin (1)

What is the general solution for sin^2(x)= 1/4 ,0<= x<= 2pi ?
The general solution for sin^2(x)= 1/4 ,0<= x<= 2pi is x= pi/6 ,x=(5pi)/6 ,x=(7pi)/6 ,x=(11pi)/6