What are the solutions to the equation 2w^2-3w-14=0 ?

The solutions to the equation 2w^2-3w-14=0 are w= 7/2 ,w=-2

Find the zeros of 2w^2-3w-14=0

The zeros of 2w^2-3w-14=0 are w= 7/2 ,w=-2

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2 w^{2} - 3 w - 14 = 0

w = \frac{7}{2}, w = - 2

Solution steps

2 w^{2} - 3 w - 14 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 14 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 14) = 11

w_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 \cdot 2}

Separate the solutions

w_{1} = \frac{- ( - 3 ) + 11}{2 \cdot 2}, w_{2} = \frac{- ( - 3 ) - 11}{2 \cdot 2}

w = \frac{- ( - 3 ) + 11}{2 \cdot 2} : \frac{7}{2}

w = \frac{- ( - 3 ) - 11}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

w = \frac{7}{2}, w = - 2

3 b^{2} + 6 b + 91 = 0

x^{2} - 12 x = - 11

lo g_{1} (2) = 3

\frac{12 q ^{- 3}}{( 3 p ^{4} q ^{- 3} ) ^{- 4}}

3 x^{2} - x - 2

What are the solutions to the equation 2w^2-3w-14=0 ?
The solutions to the equation 2w^2-3w-14=0 are w= 7/2 ,w=-2
Find the zeros of 2w^2-3w-14=0
The zeros of 2w^2-3w-14=0 are w= 7/2 ,w=-2