What is the critical 1/4 x^4-1/3 x^3-x^2 ?

The critical 1/4 x^4-1/3 x^3-x^2 is x=-1,x=0,x=2

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critical 1/4 x^4-1/3 x^3-x^2

critical points

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - x^{2}

x = - 1, x = 0, x = 2

Solution steps

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - x^{2}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 1, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

\frac{1}{4} x^{4} - \frac{1}{3} x^{3} - x^{2} : - \infty < x < \infty

All critical points are in domain

x = - 1, x = 0, x = 2

f (x) = - 2 x^{2} - 3 x + 1

(- 10, 1), (- 2, - 4)

x e^{- 3 x}

f (x) = \frac{1}{4} x^{3} + 8

What is the critical 1/4 x^4-1/3 x^3-x^2 ?
The critical 1/4 x^4-1/3 x^3-x^2 is x=-1,x=0,x=2