What are the solutions to the equation 12x^2-240x+900=0 ?

The solutions to the equation 12x^2-240x+900=0 are x=15,x=5

Find the zeros of 12x^2-240x+900=0

The zeros of 12x^2-240x+900=0 are x=15,x=5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 240 x + 900 = 0

x = 15, x = 5

Solution steps

12 x^{2} - 240 x + 900 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 240 ) \pm ( - 240 ) ^{2} - 4 \cdot 12 \cdot 900}{2 \cdot 12}

(- 240)^{2} - 4 \cdot 12 \cdot 900 = 120

x_{1, 2} = \frac{- ( - 240 ) \pm 120}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 240 ) + 120}{2 \cdot 12}, x_{2} = \frac{- ( - 240 ) - 120}{2 \cdot 12}

x = \frac{- ( - 240 ) + 120}{2 \cdot 12} : 15

x = \frac{- ( - 240 ) - 120}{2 \cdot 12} : 5

The solutions to the quadratic equation are:

x = 15, x = 5

2 x^{2} = - 3 x

\frac{n}{3} = 2

\frac{7 n}{24 n ^{3} - 64 n ^{2}} \cdot \frac{9 n - 24}{7 n}

8^{\frac{1}{3}}

s^{2} - 27 s = 0

What are the solutions to the equation 12x^2-240x+900=0 ?
The solutions to the equation 12x^2-240x+900=0 are x=15,x=5
Find the zeros of 12x^2-240x+900=0
The zeros of 12x^2-240x+900=0 are x=15,x=5