What are the solutions to the equation 100x^2-160x+63=0 ?

The solutions to the equation 100x^2-160x+63=0 are x= 9/10 ,x= 7/10

Find the zeros of 100x^2-160x+63=0

The zeros of 100x^2-160x+63=0 are x= 9/10 ,x= 7/10

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100 x^{2} - 160 x + 63 = 0

x = \frac{9}{10}, x = \frac{7}{10}

Solution steps

100 x^{2} - 160 x + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 160 ) \pm ( - 160 ) ^{2} - 4 \cdot 100 \cdot 63}{2 \cdot 100}

(- 160)^{2} - 4 \cdot 100 \cdot 63 = 20

x_{1, 2} = \frac{- ( - 160 ) \pm 20}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 160 ) + 20}{2 \cdot 100}, x_{2} = \frac{- ( - 160 ) - 20}{2 \cdot 100}

x = \frac{- ( - 160 ) + 20}{2 \cdot 100} : \frac{9}{10}

x = \frac{- ( - 160 ) - 20}{2 \cdot 100} : \frac{7}{10}

The solutions to the quadratic equation are:

x = \frac{9}{10}, x = \frac{7}{10}

a + 3 = 0

x^{2} + 6 x + 16 = 0

5 x^{2} + 25 x - 1500 = 0

4 x^{2} - 28 x + 24 = 0

(x + 4) (x + 9) (5 - x) \leq 0

What are the solutions to the equation 100x^2-160x+63=0 ?
The solutions to the equation 100x^2-160x+63=0 are x= 9/10 ,x= 7/10
Find the zeros of 100x^2-160x+63=0
The zeros of 100x^2-160x+63=0 are x= 9/10 ,x= 7/10