What are the solutions to the equation r^2+8r=0 ?

The solutions to the equation r^2+8r=0 are r=0,r=-8

Find the zeros of r^2+8r=0

The zeros of r^2+8r=0 are r=0,r=-8

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r^{2} + 8 r = 0

r = 0, r = - 8

Solution steps

r^{2} + 8 r = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 0 = 8

r_{1, 2} = \frac{- 8 \pm 8}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 8 + 8}{2 \cdot 1}, r_{2} = \frac{- 8 - 8}{2 \cdot 1}

r = \frac{- 8 + 8}{2 \cdot 1} : 0

r = \frac{- 8 - 8}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

r = 0, r = - 8

3 x^{2} - 2 x + 8 = 0

164883 (1 + \frac{45.26}{9.8})

\frac{1}{4} - \frac{1}{8}

0 = x^{2} + 6 x + 13

c^{2} - 9 c - 10

What are the solutions to the equation r^2+8r=0 ?
The solutions to the equation r^2+8r=0 are r=0,r=-8
Find the zeros of r^2+8r=0
The zeros of r^2+8r=0 are r=0,r=-8