What are the solutions to the equation a^2=4a ?

The solutions to the equation a^2=4a are a=4,a=0

Find the zeros of a^2=4a

The zeros of a^2=4a are a=4,a=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

a^{2} = 4 a

a = 4, a = 0

Solution steps

a^{2} = 4 a

Move

4 a

to the left side

a^{2} - 4 a = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 0 = 4

a_{1, 2} = \frac{- ( - 4 ) \pm 4}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 4 ) + 4}{2 \cdot 1}, a_{2} = \frac{- ( - 4 ) - 4}{2 \cdot 1}

a = \frac{- ( - 4 ) + 4}{2 \cdot 1} : 4

a = \frac{- ( - 4 ) - 4}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

a = 4, a = 0

\frac{2 π}{3} \cdot \frac{1}{4}

- \frac{33}{x + 3} \geq - \frac{16}{x} - 1

3 x^{2} + 23 x - 8 = 0

125 - 8 y^{3}

x^{3} + 6 x^{2} + 9 x + 2

What are the solutions to the equation a^2=4a ?
The solutions to the equation a^2=4a are a=4,a=0
Find the zeros of a^2=4a
The zeros of a^2=4a are a=4,a=0