What are the solutions to the equation x^2+4x=9 ?

The solutions to the equation x^2+4x=9 are x=-2+sqrt(13),x=-2-sqrt(13)

Find the zeros of x^2+4x=9

The zeros of x^2+4x=9 are x=-2+sqrt(13),x=-2-sqrt(13)

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x^{2} + 4 x = 9

x = - 2 + 13, x = - 2 - 13

Solution steps

x^{2} + 4 x = 9

Move

9

to the left side

x^{2} + 4 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 9) = 213

x_{1, 2} = \frac{- 4 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 13}{2 \cdot 1}

x = \frac{- 4 + 2 13}{2 \cdot 1} : - 2 + 13

x = \frac{- 4 - 2 13}{2 \cdot 1} : - 2 - 13

The solutions to the quadratic equation are:

x = - 2 + 13, x = - 2 - 13

(x + 7) (x - 3) = 24

81 x^{2} - 36 x + 4 = 0

(\frac{7}{10})^{2}

x^{2} - 90 x - 16200 = 0

\frac{1}{9} - \frac{1}{12}

What are the solutions to the equation x^2+4x=9 ?
The solutions to the equation x^2+4x=9 are x=-2+sqrt(13),x=-2-sqrt(13)
Find the zeros of x^2+4x=9
The zeros of x^2+4x=9 are x=-2+sqrt(13),x=-2-sqrt(13)