What is the derivative of (10x/(x^2+1)) ?

The derivative of (10x/(x^2+1)) is (10(-x^2+1))/((x^2+1)^2)

What is the first derivative of (10x/(x^2+1)) ?

The first derivative of (10x/(x^2+1)) is (10(-x^2+1))/((x^2+1)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{10 x}{x ^{2} + 1})

\frac{10 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{10 x}{x ^{2} + 1})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 10 \frac{d}{d x} (\frac{x}{x ^{2} + 1})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 10 \cdot \frac{\frac{d x}{d x} ( x ^{2} + 1 ) - \frac{d}{d x} ( x ^{2} + 1 ) x}{( x ^{2} + 1 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 1) = 2 x

= 10 \cdot \frac{1 \cdot ( x ^{2} + 1 ) - 2 xx}{( x ^{2} + 1 ) ^{2}}

Simplify

10 \cdot \frac{1 \cdot ( x ^{2} + 1 ) - 2 xx}{( x ^{2} + 1 ) ^{2}} : \frac{10 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

= \frac{10 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

(3 x + 8)^{2}

\int cos (7 t) d t

2 x^{3} - 1

y = (1 + 2 x)^{11}, (0, 1)

\frac{( 2 s - 1 )}{s ^{2} ( s + 1 ) ^{3}}

What is the derivative of (10x/(x^2+1)) ?
The derivative of (10x/(x^2+1)) is (10(-x^2+1))/((x^2+1)^2)
What is the first derivative of (10x/(x^2+1)) ?
The first derivative of (10x/(x^2+1)) is (10(-x^2+1))/((x^2+1)^2)