What is the derivative of f(x)=(x^2)/(1+4x) ?

The derivative of f(x)=(x^2)/(1+4x) is (2x+4x^2)/((1+4x)^2)

What is the first derivative of f(x)=(x^2)/(1+4x) ?

The first derivative of f(x)=(x^2)/(1+4x) is (2x+4x^2)/((1+4x)^2)

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derivative of

f (x) = \frac{x ^{2}}{1 + 4 x}

\frac{2 x + 4 x ^{2}}{( 1 + 4 x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x ^{2}}{1 + 4 x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x ^{2} ) ( 1 + 4 x ) - \frac{d}{d x} ( 1 + 4 x ) x ^{2}}{( 1 + 4 x ) ^{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1 + 4 x) = 4

= \frac{2 x ( 1 + 4 x ) - 4 x ^{2}}{( 1 + 4 x ) ^{2}}

Expand

2 x (1 + 4 x) - 4 x^{2} : 2 x + 4 x^{2}

= \frac{2 x + 4 x ^{2}}{( 1 + 4 x ) ^{2}}

\int \frac{1}{( arcsin ( x ) ) ^{3} 1 - x ^{2}} d x

e^{4 (t - 3)}

x \to 1 - lim (\frac{- 1}{x ^{2} - 1})

\int \frac{1}{1 - 5 x} d x

\frac{d r}{d θ} r = (7 + sec (θ)) sin (θ)

What is the derivative of f(x)=(x^2)/(1+4x) ?
The derivative of f(x)=(x^2)/(1+4x) is (2x+4x^2)/((1+4x)^2)
What is the first derivative of f(x)=(x^2)/(1+4x) ?
The first derivative of f(x)=(x^2)/(1+4x) is (2x+4x^2)/((1+4x)^2)