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domain of f(x)=sqrt(x+2)-1/(x^2-1)domain critical f(x)=(x+5)^{2/3}critical points inverse of y=18x-17inverse domain of f(x)=(x+3)/(4-sqrt(x^2-9))domain domain of f(x)=(x-3)/(x^2-9)domain
Frequently Asked Questions (FAQ)
What is the midpoint (-7,-9),(-0.5,-3) ?
The midpoint (-7,-9),(-0.5,-3) is (-3.75,-6)