What is the domain of y=f(x)=ln(2x+1) ?

The domain of y=f(x)=ln(2x+1) is x>-1/2

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domain of y=f(x)=ln(2x+1)

domain

y = f (x) = ln (2 x + 1)

x > - \frac{1}{2}

Solution steps

Find positive values for logs:

x > - \frac{1}{2}

The function domain

x > - \frac{1}{2}

(2, - 2), (- 4, 4)

y = \frac{4}{3} x + 6, (- 4, - 1)

f (x) = \frac{x ^{2} - 3 x - 4}{x - 4}

x^{3} + 2 x^{2} - x - 2

f (x) = x^{2} - 49