What is (x-5)^2+(y-2)^2=25 ?

The solution to (x-5)^2+(y-2)^2=25 is Circle with (a,b)=(5,2),r=5

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(x-5)^2+(y-2)^2=25

(x - 5)^{2} + (y - 2)^{2} = 25

(a, b) = (5, 2), r = 5

Solution steps

(x - 5)^{2} + (y - 2)^{2} = 25

Rewrite

(x - 5)^{2} + (y - 2)^{2} = 25

in the form of the standard circle equation

(x - 5)^{2} + (y - 2)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (5, 2), r = 5

(x + 2)^{2} + (y - 5)^{2} = 16

x^{2} + y^{2} - x + 6 y + 1 = 0

x^{2} = - y^{2} + 4

3 x^{2} + 3 y^{2} + 24 x - 12 y = 0

(x + 4)^{2} + (y + 4)^{2} = 9

What is (x-5)^2+(y-2)^2=25 ?
The solution to (x-5)^2+(y-2)^2=25 is Circle with (a,b)=(5,2),r=5