What is x^2+y^2+4x+6y+4+9=12 ?

The solution to x^2+y^2+4x+6y+4+9=12 is Circle with (a,b)=(-2,-3),r=2sqrt(3)

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x^2+y^2+4x+6y+4+9=12

x^{2} + y^{2} + 4 x + 6 y + 4 + 9 = 12

(a, b) = (- 2, - 3), r = 23

Solution steps

x^{2} + y^{2} + 4 x + 6 y + 4 + 9 = 12

Rewrite

x^{2} + y^{2} + 4 x + 6 y + 4 + 9 = 12

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = (23)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 23

x^{2} + y^{2} - 20 y + 36 = 0

3 (x + \frac{3}{4})^{2} + 3 (y - \frac{1}{2})^{2} = 36

x^{2} + y^{2} + 12 x + 4 y + 15 = 0

(x - 10)^{2} + (y + 8)^{2} = 36

x^{2} + y^{2} - 4 > 0

What is x^2+y^2+4x+6y+4+9=12 ?
The solution to x^2+y^2+4x+6y+4+9=12 is Circle with (a,b)=(-2,-3),r=2sqrt(3)