What is (x-0)^2+(y-0)^2=36 ?

The solution to (x-0)^2+(y-0)^2=36 is Circle with (a,b)=(0,0),r=6

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(x-0)^2+(y-0)^2=36

(x - 0)^{2} + (y - 0)^{2} = 36

(a, b) = (0, 0), r = 6

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 36

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 36

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

(x + 0)^{2} + (y + 0)^{2} = 6

(x + 2)^{2} + (y - 2)^{2} = 16

(x + 5)^{2} + (y - 2)^{2} = 61

(x + 2)^{2} + (y + \frac{1}{2})^{2} = \frac{17}{4}

(2 x^{2} - 12 x) + (2 y^{2} + 8 y) = 24

What is (x-0)^2+(y-0)^2=36 ?
The solution to (x-0)^2+(y-0)^2=36 is Circle with (a,b)=(0,0),r=6