What is x^{(2)}+y^{(2)}-2x-4y+3=0 ?

The solution to x^{(2)}+y^{(2)}-2x-4y+3=0 is Circle with (a,b)=(1,2),r=sqrt(2)

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x^{(2)}+y^{(2)}-2x-4y+3=0

x^{(2)} + y^{(2)} - 2 x - 4 y + 3 = 0

(a, b) = (1, 2), r = 2

Solution steps

x^{2} + y^{2} - 2 x - 4 y + 3 = 0

Rewrite

x^{2} + y^{2} - 2 x - 4 y + 3 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 2)^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (1, 2), r = 2

45 x^{2} + 45 y^{2} = - 4 x

x^{2} - 2 x + y^{2} = \frac{466}{25}

(x + 1)^{2} + (y - 3)^{2} = (50)^{2}

\frac{( x - 5 ) ^{2}}{3 ^{2}} + \frac{( y + 5 ) ^{2}}{9} = 1

x^{2} - 2 x + y^{2} + 4 y = 31

What is x^{(2)}+y^{(2)}-2x-4y+3=0 ?
The solution to x^{(2)}+y^{(2)}-2x-4y+3=0 is Circle with (a,b)=(1,2),r=sqrt(2)