What is (x-0)^2+(y-0)^2=169 ?

The solution to (x-0)^2+(y-0)^2=169 is Circle with (a,b)=(0,0),r=13

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(x-0)^2+(y-0)^2=169

(x - 0)^{2} + (y - 0)^{2} = 169

(a, b) = (0, 0), r = 13

Solution steps

(x - 0)^{2} + (y - 0)^{2} = 169

Rewrite

(x - 0)^{2} + (y - 0)^{2} = 169

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 13

1^{2} = a^{2} + b^{2}

(x - 7)^{2} + (y - 9)^{2} = 9

x^{2} + y^{2} = 32 + 14 y

(x - 4)^{2} + (y + 7)^{2} = 1 1^{2}

4 x^{2} - 4 x + 4 y^{2} = 63

What is (x-0)^2+(y-0)^2=169 ?
The solution to (x-0)^2+(y-0)^2=169 is Circle with (a,b)=(0,0),r=13