What is (x-4)^2+(y+7)^2=11^2 ?

The solution to (x-4)^2+(y+7)^2=11^2 is Circle with (a,b)=(4,-7),r=11

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(x-4)^2+(y+7)^2=11^2

(x - 4)^{2} + (y + 7)^{2} = 1 1^{2}

(a, b) = (4, - 7), r = 11

Solution steps

(x - 4)^{2} + (y + 7)^{2} = 1 1^{2}

Rewrite

(x - 4)^{2} + (y + 7)^{2} = 1 1^{2}

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 7))^{2} = 1 1^{2}

Therefore the circle properties are:

(a, b) = (4, - 7), r = 11

4 x^{2} - 4 x + 4 y^{2} = 63

x^{2} + y^{2} + 4 x + 6 y = 3

x^{2} + y^{2} + 4 x + 6 y = 0

x^{2} + y^{2} - 10 x - 2 y - 3 = 0

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

What is (x-4)^2+(y+7)^2=11^2 ?
The solution to (x-4)^2+(y+7)^2=11^2 is Circle with (a,b)=(4,-7),r=11