What is x^2+y^2+4x+6y=0 ?

The solution to x^2+y^2+4x+6y=0 is Circle with (a,b)=(-2,-3),r=sqrt(13)

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x^2+y^2+4x+6y=0

x^{2} + y^{2} + 4 x + 6 y = 0

(a, b) = (- 2, - 3), r = 13

Solution steps

x^{2} + y^{2} + 4 x + 6 y = 0

Rewrite

x^{2} + y^{2} + 4 x + 6 y = 0

in the form of the standard circle equation

(x - (- 2))^{2} + (y - (- 3))^{2} = (13)^{2}

Therefore the circle properties are:

(a, b) = (- 2, - 3), r = 13

x^{2} + y^{2} - 10 x - 2 y - 3 = 0

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

(y + 5)^{2} = 100 - (x + 2)^{2}

x^{2} + y^{2} + 16 x + 14 y + 104 = 0

(x - (- 6))^{2} + (y - 9)^{2} = 1 0^{2}

What is x^2+y^2+4x+6y=0 ?
The solution to x^2+y^2+4x+6y=0 is Circle with (a,b)=(-2,-3),r=sqrt(13)