What is 4x^2-4x+4y^2=63 ?

The solution to 4x^2-4x+4y^2=63 is Circle with (a,b)=(1/2 ,0),r=4

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4x^2-4x+4y^2=63

4 x^{2} - 4 x + 4 y^{2} = 63

(a, b) = (\frac{1}{2}, 0), r = 4

Solution steps

4 x^{2} - 4 x + 4 y^{2} = 63

Rewrite

4 x^{2} - 4 x + 4 y^{2} = 63

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 0), r = 4

x^{2} + y^{2} + 4 x + 6 y = 3

x^{2} + y^{2} + 4 x + 6 y = 0

x^{2} + y^{2} - 10 x - 2 y - 3 = 0

x^{2} - 10 x + 25 + y^{2} + 6 y + 9 = 4

(y + 5)^{2} = 100 - (x + 2)^{2}

What is 4x^2-4x+4y^2=63 ?
The solution to 4x^2-4x+4y^2=63 is Circle with (a,b)=(1/2 ,0),r=4