What is (x+1)^2+(y-4)^2=52 ?

The solution to (x+1)^2+(y-4)^2=52 is Circle with (a,b)=(-1,4),r=sqrt(52)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+1)^2+(y-4)^2=52

(x + 1)^{2} + (y - 4)^{2} = 52

(a, b) = (- 1, 4), r = 52

Solution steps

(x + 1)^{2} + (y - 4)^{2} = 52

Rewrite

(x + 1)^{2} + (y - 4)^{2} = 52

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 4)^{2} = (52)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 4), r = 52

x^{2} + (y + \frac{1}{2})^{2} = \frac{1}{4}

9 x^{2} + 54 x + 9 y^{2} - 6 y + 28 = 0

x^{2} + y^{2} + 6 x - 22 y + 66 = 0

x^{2} + y^{2} - 12 x + 24 y + 116 = 0

a^{2} = 5 - b^{2}

What is (x+1)^2+(y-4)^2=52 ?
The solution to (x+1)^2+(y-4)^2=52 is Circle with (a,b)=(-1,4),r=sqrt(52)