What is (x-7.5)^2+(y-7.84)^2=0.56^2 ?

The solution to (x-7.5)^2+(y-7.84)^2=0.56^2 is Circle with (a,b)=(7.5,7.84),r=0.56

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(x-7.5)^2+(y-7.84)^2=0.56^2

(x - 7.5)^{2} + (y - 7.84)^{2} = 0.5 6^{2}

(a, b) = (7.5, 7.84), r = 0.56

Solution steps

(x - 7.5)^{2} + (y - 7.84)^{2} = 0.5 6^{2}

Rewrite

(x - 7.5)^{2} + (y - 7.84)^{2} = 0.5 6^{2}

in the form of the standard circle equation

(x - 7.5)^{2} + (y - 7.84)^{2} = 0.5 6^{2}

Therefore the circle properties are:

(a, b) = (7.5, 7.84), r = 0.56

3 = 3 x^{2} + 3 y^{2}

x^{2} - 8 x + y^{2} - 6 y + 25 = 1

x^{2} + y^{2} + 6 x - 2 x - 2 y + 1 = 0

x^{2} + y^{2} - 6 x - 2 y = 15

x^{2} + 2 x + y^{2} - 6 y = 15

What is (x-7.5)^2+(y-7.84)^2=0.56^2 ?
The solution to (x-7.5)^2+(y-7.84)^2=0.56^2 is Circle with (a,b)=(7.5,7.84),r=0.56