What is the radius (x+8)^2+(y+5)^2=3^2 ?

The radius (x+8)^2+(y+5)^2=3^2 is r=3

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radius (x+8)^2+(y+5)^2=3^2

radius

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

r = 3

Solution steps

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

Rewrite

(x + 8)^{2} + (y + 5)^{2} = 3^{2}

in the form of the standard circle equation

(x - (- 8))^{2} + (y - (- 5))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 8, - 5), r = 3

And the radius is:

r = 3

(x + 1)^{2} + (y - 2)^{2} = 9

x^{2} + (y - 1)^{2} = 1

x^{2} + (y - 5)^{2} = 25

x^{2} + y^{2} - 2 y - 8 = 0

(x + 3)^{2} + (y - 3)^{2} = 8