What is the radius x^2+y^2-2x-8y-19=0(1.5) ?

The radius x^2+y^2-2x-8y-19=0(1.5) is r=6

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radius x^2+y^2-2x-8y-19=0(1.5)

radius

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 (1.5)

r = 6

Solution steps

x^{2} + y^{2} - 2 x - 8 y - 19 = 0 \cdot 1.5

Rewrite

x^{2} + y^{2} - 2 x - 8 y - 19 = 01.5

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 6

And the radius is:

r = 6

x^{2} + y^{2} + 10 x + 8 y - 4 = 0

(x - 3)^{2} + (y - 5)^{2} = 24

x^{2} + y^{2} + 4 x - 6 y - 12 = 0

x^{2} - 8 x + y^{2} + 6 y = - 9

(x + 1)^{2} + (y - 5)^{2} = 5^{2}

What is the radius x^2+y^2-2x-8y-19=0(1.5) ?
The radius x^2+y^2-2x-8y-19=0(1.5) is r=6