What is the radius (x-10)^2+y^2= 1/4 ?

The radius (x-10)^2+y^2= 1/4 is r= 1/2

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radius (x-10)^2+y^2= 1/4

radius

(x - 10)^{2} + y^{2} = \frac{1}{4}

r = \frac{1}{2}

Solution steps

(x - 10)^{2} + y^{2} = \frac{1}{4}

Rewrite

(x - 10)^{2} + y^{2} = \frac{1}{4}

in the form of the standard circle equation

(x - 10)^{2} + (y - 0)^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (10, 0), r = \frac{1}{2}

And the radius is:

r = \frac{1}{2}

4 x^{2} + 4 y^{2} + 24 x - 32 y + 91 = 0

x^{2} + 16 x + y^{2} - 12 y = 0

(x - 2.5)^{2} + (y - 0.5)^{2} = 14.5

(x - 5)^{2} + (y - 12)^{2} = 9

4 x^{2} + 4 y^{2} - 16 = 0