What is the radius (x-3)^2+(y+3)^2=36 ?

The radius (x-3)^2+(y+3)^2=36 is r=6

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radius (x-3)^2+(y+3)^2=36

radius

(x - 3)^{2} + (y + 3)^{2} = 36

r = 6

Solution steps

(x - 3)^{2} + (y + 3)^{2} = 36

Rewrite

(x - 3)^{2} + (y + 3)^{2} = 36

in the form of the standard circle equation

(x - 3)^{2} + (y - (- 3))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, - 3), r = 6

And the radius is:

r = 6

(x + 3)^{2} + (y + 1)^{2} = 4

x^{2} + y^{2} + 6 x + 2 y - 54 = 0

2 x^{2} + 2 y^{2} = 8

x^{2} + y^{2} - 10 x + 2 y + 17 = 0

(x - 1)^{2} + (y + 2)^{2} = 16