What is the radius x^2+y^2-10x+2y+17=0 ?

The radius x^2+y^2-10x+2y+17=0 is r=3

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radius x^2+y^2-10x+2y+17=0

radius

x^{2} + y^{2} - 10 x + 2 y + 17 = 0

r = 3

Solution steps

x^{2} + y^{2} - 10 x + 2 y + 17 = 0

Rewrite

x^{2} + y^{2} - 10 x + 2 y + 17 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, - 1), r = 3

And the radius is:

r = 3

(x - 1)^{2} + (y + 2)^{2} = 16

x^{2} + y^{2} + 6 x - 4 y + 12 = 0

(x - 2)^{2} + (y - (- 5))^{2} = 97

(x - 5)^{2} + y^{2} = 9

x^{2} - 4 x + 12 y + y^{2} + 14 = 0