ar

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x^2+y^2=2

الحلّ

2 x^{2} + y^{2} = 2

الحلّ

(h, k) = (0, 0), a = 1, b = 2

خطوات الحلّ

2 x^{2} + y^{2} = 2

Rewrite

2 x^{2} + y^{2} = 2

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{1 ^{2}} + \frac{( y - 0 ) ^{2}}{( 2 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 1, b = 2

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 2, a = 1

أمثلة شائعة

(x - 3)^{2} + y^{2} = 4

directrix y=-4x^2 directrix

y = - 4 x^{2}

vertices (x^2}{25}-\frac{y^2)/9 =1 vertices

\frac{x ^{2}}{25} - \frac{y ^{2}}{9} = 1

x^{2} - 2 x - 4 y + 9 = 0

4 x^{2} + 25 y^{2} = 100